x^2+3.3X-0.7=0

Solution for x^2+3.3X-0.7=0 equation:

x^2+3.3x-0.7=0

a = 1; b = 3.3; c = -0.7;
Δ = b2-4ac
Δ = 3.32-4·1·(-0.7)
Δ = 13.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.3)-\sqrt{13.69}}{2*1}=\frac{-3.3-\sqrt{13.69}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.3)+\sqrt{13.69}}{2*1}=\frac{-3.3+\sqrt{13.69}}{2}
$